Cannot get loginrealms to work with 2.0.16
Michael Fair
michael at daclubhouse.net
Mon Sep 16 21:16:17 EDT 2002
> >A properly configured environment would:
> >A) Have unixheirsep turned on
> >
> schulte-00:18:46:~/cyrus-imapd-2.0.16 >for i in `find .`;do grep
> "unixheirsep" $i; done
> schulte-00:19:01:~/cyrus-imapd-2.0.16 >
>
> I cannot find the string unixheirsep in the whole source distribution!
> Is it a cyrus specific setting or some unix system setting ? What's it
> all about ?
Three things:
1) I mispelled the option :}
2) In my imapd.conf (Cyrus 2.1.9) it is "unixhierarchysep"
3) The option may only be available as a patch to the 2.0 series
This feature converts the normal separator character "."
to "/". By making the separator "/" you can then put "."
in the names (e.g user at domain.dom).
> >B) Each user mailbox would be created with
> > cm user/user at domain.dom
> >
> Cyradm says:
>
> localhost> cm user/testtesttest at testtesttest.test
> createmailbox: Invalid mailbox name
This indicates that you are still using the standard
"." separator character. I believe it is choking on
"/" as an invalid character.
> So it seems that I am able to create a mailbox
> user.testtesttest at testtesttest
>
> saslpasswd -u testtesttest -c testtesttest
>
> but then I cannot login with testtesttest at testtesttest :-(
This is where loginrealms comes into play.
Check to makes sure you have "testtesttest" in
the loginrealms parameter of imapd.conf to
support this.
> >C) saslpasswd would have been run as:
> > saslpasswd -u domain.dom -c user
> >
> That's exactly as I did it...
>
> >D) The user would type their username as:
> > user at domain.dom
> >
> >
> ...and that's what I want ;-)
The unix hierarchy separator is key here because you
want to have a "." in the username.
> Sep 17 00:32:30 master[8185]: [ID 392559 local6.debug] about to exec
> /usr/local/bin/imapd
> Sep 17 00:32:30 service-imap[8185]: [ID 518349 local6.debug] executed
> Sep 17 00:32:30 imapd[8185]: [ID 921384 local6.debug] accepted connection
>
> and nothing more !
Hmm you should ordinarily get some sort of success/failure of
the person trying to authenticate..... Check the above problems
and if this is still continuing then dig a bit deeper....
-- Michael --
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